00:01
Assign e or z configurations to the following alkenes.
00:08
A, let's rank substitutes on the left.
00:14
Ethel group ranks higher than methyl group.
00:21
Let's rank substitutions on the right.
00:24
Chlorine ranks higher than hydroxymethyl.
00:34
Then we'll pick winners from each side, and they are located on the same.
00:41
Same side of the double bond.
00:43
So the configuration is z.
00:48
B, on the left side, chlorine has high priority over methoxy, because chlorine is heavier than oxygen.
00:59
On the right side, the propyl group has higher priority over the effort group.
01:07
Now the winners are located on the opposite sides of the double bond, and the configuration is e.
01:22
See, on the left, when we go to the next carbon, we cannot make a choice.
01:32
Let's move to the next carbon...