Question

Using Thevenin’s theorem, find the equivalent circuit to the left of the terminals in the circuit shown below. Hence find i. 6 ? 6 ? a i 12 V 2 A 4 ? 1 ? b V_TH = 6V, R_TH = 3?, i = 1.5A

          Using Thevenin’s theorem, find the equivalent circuit to the left of the terminals in the circuit shown below. Hence find i.

6 ? 6 ?
a
i
12 V 2 A 4 ? 1 ?
b

V_TH = 6V, R_TH = 3?, i = 1.5A

Using Thevenin’s theorem, find the equivalent circuit to the left of the terminals in the circuit shown below. Hence find i.

6 ? 6 ?
a
i
12 V 2 A 4 ? 1 ?
b

VTH = 6V, RTH = 3?, i = 1.5A

Added by Christine P.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Adi S

11/03/2022

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First, we need to find the Thevenin equivalent voltage (Vth) and Thevenin equivalent resistance (Rth) for the circuit. Show more…

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Using Thevenin’s theorem, find the equivalent circuit to the left of the terminals in the circuit shown below. Hence find i. V_TH = 6V, R_TH = 3Ω, i = 1.5A

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Transcript

00:01 Let us use the heaven to convert the given circuit.

00:04 So according to the given circuit, let us apply the thevenin theorem to the left of the given terminals a and b.

00:10 So applying the thevenin theorem to the left of a and b.

00:13 So we can see that 1 old and 6 oam using this.

00:20 Let us consider or convert it into a current source.

00:25 So when we are converting it into a current source, we know that the current through 6 home reservoirs.

00:30 I is going to be v divided by r which is nothing but 12 divided by 6 which is going to be a 2 ampere source so our 7 in equivalent circuit for this is going to be if this is a current source here is our 6 oom and then we have a current source of 2 ampere and then we have a 6 o resistance and then we have the terminals a and b so this is a 2 ampere source this is the 2 ampere source and this is our 6 om this is our 6 home this is our 4 om now as we can see these two two current sources are in parallel so we can add the current sources so add current sources as they are in parallel connection so when we add them the equivalent current source is going to be the 4 ampere current source hence we can write that circuit further as so sure we have the current source so sure we have the current source here we have a 6 om here we have a 6 om and then here we have a 4 om and then we have terminals a b this is 4 6 6 and this is our 4 ampere current source now as we can see in the circuit we can further convert our 4 amp current source and our 6 om resistor into a voltage source so if we are if we are connecting that as a voltage source because across the 6 -home resistance the current is going to be 4 ampier so considering converting 4 ampere and 6 -home to current sorry a voltage source what are we going to get we know that potential difference is simply going to be i times our current is 4 potential difference is 6 so which is going to be 24 volt voltage source.

02:43 So this 24 volt voltage source and the remaining resistors would now look in a particular connection and that connection is going to be now.

02:53 So we have a voltage source.

02:55 So we'll replace it as voltage.

03:07 6a.

03:09 C.

03:10 This is 4.

03:11 6 .6 .24.

03:13 So this can be equivalent to a 24...

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