a V1 (t) = 0.4t³+4t²+3 Eq. 2.4 1 V2 (t) = log (7t)+ln t² Eq. 2.5 V3 (t) = sin² (4t) - 3cos (t) Eq. 2.6 According to (equations 2.4, 2.5, and 2.6), determine the rate of change for each belt with respect to time to find the equation of acceleration for each. b) Use integral methods to find the distance between the first conveyer belt and the third conveyer belt. c) Use integral methods to find: T (t) = 3.4 t? – 15 t? + 8.3 Eq. 3.3
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To find the rate of change for each belt, we need to take the derivative of each equation with respect to time. For equation 2.4: V1'(t) = d/dt (0.4t^3 + 4t^2 + 3) = 1.2t^2 + 8t For equation 2.5: V'(t) = d/dt (log(7t) + ln) = 1/t For equation Show more…
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