Question

$V_{in} = 50 mV$ $R_1 = 100 k\Omega$ $R_2 = 10 k\Omega$ $R_3 = 10 k\Omega$ With a constant input of 50 mV, the output ranges from Note: The Potentiometer R3 can take values from 0 to 10 kOhm

Name: vin 50 mv r1 100 komega r2 10 komega r3 10 komega with a constant input of 50 mv the output ranges from note the potentiometer r3 can take values from 0 to 10 kohm 29648
Uploaded: 2023-09-12T17:17:51-08:00
Duration: 1 min 22 s
Channel: Adi S
Description: vin 50 mv r1 100 komega r2 10 komega r3 10 komega with a constant input of 50 mv the output ranges from note the potentiometer r3 can take values from 0 to 10 kohm 29648

          $V_{in} = 50 mV$
$R_1 = 100 k\Omega$
$R_2 = 10 k\Omega$
$R_3 = 10 k\Omega$
With a constant input of 50 mV, the output ranges from
Note: The Potentiometer R3 can take values from 0 to 10 kOhm

vin 50 mv r1 100 komega r2 10 komega r3 10 komega with a constant input of 50 mv the output ranges from note the potentiometer r3 can take values from 0 to 10 kohm 29648

Added by Ricardo C.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Adi S

09/12/2023

Step 1

The output voltage $V_{out}$ can be calculated using the formula for an inverting amplifier: $V_{out} = -V_{in} \frac{R_f}{R_{in}}$ where $R_{in}$ is the input resistance and $R_f$ is the feedback resistance. In this circuit, $R_{in} = R_2 || R_3$ and $R_f = R_1$. Show more…

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$V_{in} = 50 mV$ $R_1 = 100 k\Omega$ $R_2 = 10 k\Omega$ $R_3 = 10 k\Omega$ With a constant input of 50 mV, the output ranges from Note: The Potentiometer R3 can take values from 0 to 10 kOhm