00:01
Hello friends, let us have a look on this question.
00:02
We have to find for a single stage bjt amplifier circuit as shown above, find out the following we have to find, this is many thing that given in the questions.
00:11
So, first of all, first what i am doing, i am just applying here the kcl rule applying here, sorry kvl rule on this circuit that we have given.
00:22
So, minus 6 plus we can say ie plus re plus vbe plus ib and rb that is equal to 0.
00:35
So, as we can see ie equal to c1 plus beta ib.
00:43
So, we can say ib is equal to 6 minus 0 .7 and divide by 10 k plus 101 multiply with 3 k is equal to 16 .9 micro ampere, this is the value of the ib that we found here.
01:01
So, from this i can see the ic is equal to beta ib very good.
01:06
So, here it will get the 91 .69 milli ampere it is equal to the ic value.
01:11
Now, if i just find the value of the gm here what i will get, i will get ic by vt.
01:18
So, what is ic what found here 1 .69 milli ampere divide by 26 milli volt.
01:25
So, we will get 65 milli by v that is the answer.
01:31
Now, getting the value of the re here.
01:33
So, what i will get, i will get vt by ic means just opposite of this.
01:39
So, i will get 15 .38 ohm for this value...