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VECTORS (PART 2) |R1| = 4 |R2| = 4 |R1| means the magnitude of R1 We will now add R1 and R2 analytically. Here are the steps 1) Decompose R1 and R2 into their respective x and y components: R1: |x1| = |R1| cos 60° = 4 cos 60° = 2 |y1| = |R1| sin 60° = 4 sin 60° = 3.46 R2: |x2| = |R2| cos 60° = 4 cos 60° = 2 |y2| = -|R2| sin 60° = -4 sin 60° = -3.46 y2 points downward (see Figure)

          VECTORS (PART 2)
|R1| = 4
|R2| = 4
|R1| means the magnitude of R1
We will now add R1 and R2 analytically. Here are the steps
1) Decompose R1 and R2 into their respective x and y components:
R1:
|x1| = |R1| cos 60° = 4 cos 60° = 2
|y1| = |R1| sin 60° = 4 sin 60° = 3.46
R2:
|x2| = |R2| cos 60° = 4 cos 60° = 2
|y2| = -|R2| sin 60° = -4 sin 60° = -3.46
y2 points downward (see Figure)

VECTORS (PART 2)
|R1| = 4
|R2| = 4
|R1| means the magnitude of R1
We will now add R1 and R2 analytically. Here are the steps
1) Decompose R1 and R2 into their respective x and y components:
R1:
|x1| = |R1| cos 60° = 4 cos 60° = 2
|y1| = |R1| sin 60° = 4 sin 60° = 3.46
R2:
|x2| = |R2| cos 60° = 4 cos 60° = 2
|y2| = -|R2| sin 60° = -4 sin 60° = -3.46
y2 points downward (see Figure)

Added by Celia B.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Supratim Pal

05/06/2022

Step 1

\( \vec{R_{1x}} = \vec{R_1} \cos(60^\circ) = 4 \cos(60^\circ) = 2 \) \( \vec{R_{1y}} = \vec{R_1} \sin(60^\circ) = 4 \sin(60^\circ) = 3.46 \) ** Show more…

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VECTORS (PART 2) |R1| = 4 |R2| = 4 |R1| means the magnitude of R1 We will now add R1 and R2 analytically. Here are the steps 1) Decompose R1 and R2 into their respective x and y components: R1: |x1| = |R1| cos 60 = 4 cos 60 = 2 |y1| = |R1| sin 60 = 4 sin 60 = 3.46 R2: |x2| = |R2| cos 60 = 4 cos 60 = 2 |y2| = -|R2| sin 60 = -4 sin 60 = -3.46 y2 points downward (see Figure)