00:01
So here in this problem we have been given that there are two vectors, vector 1 and vector 2 represented by v1 and v2, and the magnitude of this two vectors are 6 .6 and 8 .5 units respectively, and v1 vector is pointing along negative direction of x -axis.
00:27
So here this is the direction of v1 vector.
00:31
And v2 vector is at an angle of 45 degree with respect to positive direction of x -axis.
00:41
And now here we need to figure out the x as well as the y component of these two vectors, v1 and v2.
00:50
So we observe that v1 is completely lying along x direction.
00:55
So let's create here at the table.
00:57
This is vector v1 and this is vector v2.
01:00
And here we will write the x component and here we will write the y components so for vector one the x component would be minus 6 .6 and there will be no y component because it's completely lying along x direction whereas here vector 2 we need to use the sign and cost ratio here so its length is representing the magnitude that's 8 .5 we have been given and this is 45 so you its x component here can be found by using cost ratio.
01:34
So cost 45 will be x by 8 .5.
01:38
So from here we get the value of x as 8 .5 into cost 45, which is 1 by root 2.
01:45
So here when we divide 8 .5 with 1 by root 2, we multiply it with 1 by root 2, we get the result as 6 approximately.
01:57
So that is the x component.
01:59
And similarly, we use sign ratio.
02:03
So basically cost 45 and sine 45 they are same.
02:06
So x and y component both will be approximately same...