Question

Velocity (m/s) 10 5 0 2 4 6 8 10 12 14 16 Time (s) -5 -10 The total distance traveled by the object during the indicated 14 s is (A) 7.5 m (B) 25 m (C) 62.5 m (D) 77.5 m The total displacement of the object during the 14 s indicated is (A) 7.5 m (B) 25 m (C) 62.5 m (D) 77.5 m The average velocity over the whole time, in meters per second, of the object is (A) 0 (B) 0.5 (C) 2.5 (D) 4.5

          Velocity (m/s)
10
5
0
2 4 6 8 10 12 14 16 Time (s)
-5
-10
The total distance traveled by the object during the indicated 14 s is
(A) 7.5 m
(B) 25 m
(C) 62.5 m
(D) 77.5 m
The total displacement of the object during the 14 s indicated is
(A) 7.5 m
(B) 25 m
(C) 62.5 m
(D) 77.5 m
The average velocity over the whole time, in meters per second, of the object is
(A) 0
(B) 0.5
(C) 2.5
(D) 4.5

Velocity (m/s)
10
5
0
2 4 6 8 10 12 14 16 Time (s)
-5
-10
The total distance traveled by the object during the indicated 14 s is
(A) 7.5 m
(B) 25 m
(C) 62.5 m
(D) 77.5 m
The total displacement of the object during the 14 s indicated is
(A) 7.5 m
(B) 25 m
(C) 62.5 m
(D) 77.5 m
The average velocity over the whole time, in meters per second, of the object is
(A) 0
(B) 0.5
(C) 2.5
(D) 4.5

Added by Madison B.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Supreeta N

06/15/2023

Step 1

First, we need to find the distance traveled during the first 10 seconds when the velocity is 10 m/s. Since the velocity is constant, we can use the formula: Distance = Velocity × Time Distance = 10 m/s × 10 s = 100 m Show more…

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Thanks for your feedback!

Velocity (m/s) Time (s) The total distance traveled by the object during the indicated 14 s is (A) 7.5 m (B) 25 m (C) 62.5 m (D) 77.5 m The total displacement of the object during the 14 s indicated is (A) 7.5 m (B) 25 m (C) 62.5 m (D) 77.5 m The average velocity over the whole time, in meters per second, of the object is (A) 0 (B) 0.5 (C) 2.5 (D) 4.5