velocity vector C lies on the x-y plane. It points 60 degrees counterclockwise from +x and has magnitude of 2 meters. You divide this vector by a negative scalar -6 sec. What is the direction and magnitude?
Added by Robert P.
Step 1
With magnitude 2 and angle 60° CCW from +x, C = 2⟨cos60°, sin60°⟩ = 2⟨1/2, sqrt(3)/2⟩ = ⟨1, sqrt(3)⟩ (units: m/s if C is a velocity). Show more…
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