Verifica en cada caso si el punto P pertenece a la circunferencia dada. a. P(5,66, -2): $x^2 + y^2 = 36$ b. P(4, 2): $x^2 + y^2 = 20$ c. P(6, -6): $x^2 + y^2 = 72$
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P(5, 6) A + Y' = 36 To verify if the point P(5, 6) belongs to the circumference A + Y' = 36, we substitute the coordinates of P into the equation: 5 + 6 = 36 11 = 36 Since 11 is not equal to 36, the point P(5, 6) does not belong to the given circumference A + Y' = Show more…
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