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In this problem, it is said that the length of a rectangle is 4 more than double the width.
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The perimeter is given to be 98 inches.
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We need to find the dimensions of the rectangle.
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So we have the length and the width.
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So the width is w, w inches.
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And the length is 4 more than double the width.
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So 4 more than double the width.
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4 plus 2 w inches.
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This will be the length.
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We have been given the perimeter.
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The perimeter is given to be 98 inches.
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Now what is the formula for the perimeter of a rectangle? we have 2 times l plus w.
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So this is equal to 98.
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So if we divide both sides of the equation by 2, we have that l plus w is equal to 98 over 2.
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That is equal to 49.
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Now l is 4 plus 2 w...