The geosynchronous orbit is at a distance of \(3.60 \times 10^4\) km above the Earth's surface. The radius of the Earth is \(6.37 \times 10^3\) km. Therefore, the radius of the geosynchronous orbit \(r_g\) is:
\[
r_g = 6.37 \times 10^3 + 3.60 \times 10^4 = 4.237
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