(vi) The marginal revenue function (in thousands of rupees) of a particular (3) commodity is \( 5+e^{-0.02 x} \), where \( x \) denotes the number of units sold. Determine the total revenue from the sale of 150 units. Q2) Attempt any five of the following six questions (i) A plant produces y tons of copper per week at a total cost of Rs \( \frac{1}{10} y^{3}-3 y^{2}+50 y+300 \) If the market price is fixed at Rs \( 33_{3}^{1} \), find the profit maximizing output of plant and the maximum profit? Shbuld the firm continue production? Justify?
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Q6: a) The marginal revenue function for a company's product is MR = 50000 - x Where x equals the number of units produced and sold. If total revenue equals 0 when no units are sold, determine the total revenue function for the product.
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Title: Marginal Cost, Revenue, and Profit for Producing LCD TVs A company manufactures a series of 20-inch flat-tube LCD televisions. The quantity x of these sets demanded each week is related to the wholesale unit price p by the following equation: p = -0.005x + 190 The weekly total cost (in dollars) incurred by Pulsar for producing x sets is represented by the following equation: C(x) = 0.000001x^3 - 0.02x^2 + 120x + 70,000 (a) Find the revenue function R. R(x) = 0.05x^2 + 190x (b) Find the profit function P. P(x) = R(x) - C(x) (c) Find the marginal cost function C'. C'(x) = 0.000003x^2 - 0.04x + 120 (d) Find the marginal revenue function R'. R'(x) = 0.10x + 190 (e) Find the marginal profit function P'. P'(x) = R'(x) - C'(x)
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The revenue from the sale of industrial motors is R = 350x + 420(3x + 4)^-1 - 200, where x is the number of units sold. R' = You do not need to expand your answer. The marginal revenue, rounded to 2 decimal places, when 50 units are sold, is If 51 units were sold, the revenue will change by about
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