If X is normally distributed with mean 100 and standard deviation 8, what is P(90 < X < 112)? 0.8276 0.0388 0.3944 0.4332
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The z-score formula is: $z = \frac{X - \mu}{\sigma}$ where $X$ is the value, $\mu$ is the mean, and $\sigma$ is the standard deviation. For $X = 90$, the z-score is: $z_1 = \frac{90 - 100}{8} = -1.25$ For $X = 112$, the z-score is: Show more…
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