In the figure four particles are fixed along an x axis,...

Name: In the figure four particles are fixed along an x axis, separated by distances d = 4.60 cm. The charges are q1 = +4e, q2 = -e, q3 = +e, and q4 = +12e, with e = 1.60 × 10^-19 C. What is the value of the net electrostatic force on (a) particle 1 and (b) particle 2 due to the other particles?
Uploaded: 2022-05-26T03:04:36-08:00
Duration: 5 min 1 s
Channel: Manoj Rathi
Description: In the figure four particles are fixed along an x axis, separated by distances d = 4.60 cm. The charges are q1 = +4e, q2 = -e, q3 = +e, and q4 = +12e, with e = 1.60 × 10^-19 C. What is the value of the net electrostatic force on (a) particle 1 and (b) particle 2 due to the other particles?

In the figure four particles are fixed along an x axis, separated by distances d = 4.60 cm. The charges are $q_1 = +4e$, $q_2 = -e$, $q_3 = +e$, and $q_4 = +12e$, with $e = 1.60 \times 10^{-19}$ C. What is the value of the net electrostatic force on (a) particle 1 and (b) particle 2 due to the other particles?

Transcript

00:01 Question what is the magnet of the nit electrostatic force acting on particle one which is over here due to the particles two and three if the distance between q1 and q2 is one uh q1 and q2 is one meter so this one is one meter as in the value of r is one so this will definitely be three -fourth of r that is three over four okay so q1 is a positive charge q three is a negative charge charge and q2 is a positive charge.

00:33 So because of q2, let's call the forces f2.

00:37 The force is going to be repulsive in nature.

00:39 So that will be f2 over here.

00:40 Because of q3, that's going to be attractive in nature.

00:44 So the value of f2 will be k, q1, q2 over r square where r is just one.

00:52 So that's one square, which is over on the left.

00:55 And the value of f3 is going to be k, q1, q3 over.

01:01 Zero uh three over four right three over four whole square which is over on the right uh so uh the net magnitude the net the net force is going to be the uh difference of the of these two because they are in opposite direction so that's got to be k q1 q2 over k k k k u2 over 1 minus k q1 q 3 over 4 right what is common here? i think kq1 is a common factor we are left with q2 minus 4 over 3 q3 over here value of k is 9 times 10 raised to 9 the value of q1 is 1 .6 times 10 raised 2 minus seems like when let me just zoom this up okay i think that's negative 19 as far as i i can see because the image is a bit blurred.

02:10 Okay.

02:14 So over here we have the value of q1 as 1 .6 times 10 raise to minus 19.

02:24 And then q2 is 3 .2 times 10 raise to minus 19...

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