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#01. Simplify. (a) ((1)/(2)x^(4))(16x^(5)) (b) (-3x^(-2))(4x^(4)) (c) ((2x^(3))(3x^(2)))/((x^(2))^(3)) (d) ((2x^(2))^(3)y^(2))/(4x^(4)y^(2)) (e) ((1)/(6)a^(5))(-3a^(2))(4a^(7)) (f) ((6x^(3))^(2))/((2x^(2))^(3))(3x^(2))^(0) (g) ((4a^(2)b)/(a^(3)b^(2)))((5a^(2)b)/(2b^(4))) (h) ((1)/(3)x^(4)y^(-3))^(-2) (i) (3y^(3))^(4)(4y^(2))^(-3) (j) ((3x^(5)y^(4)z)/(x^(0)y^(-3)z))^(2) #02. Simplify the expression and rationalize the denominator when appropriate. (a) sqrt(81) (b) oot(3)(-216) (c) oot(4)(512) (d) (1)/( oot(3)(2)) (e) sqrt((1)/(5)) (f) sqrt(9x^(-4)y^(6)) (g) oot(3)(8a^(6)b^(-3)) (h) oot(4)(81r^(5)s^(8)) (i) sqrt((3x)/(2y^(3))) (j) oot(3)((2x^(4)y^(4))/(9x)) (k) oot(4)((5x^(8)y^(3))/(27x^(2))) (l) oot(4)((5x^(5)y^(-2))^(4)) (m) oot(5)((8x^(3))/(y^(4))) oot(5)((4x^(4))/(y^(2))) (n) sqrt(5xy^(7))sqrt(15x^(3)y^(3)) (o) oot(3)(3t^(4)v^(2)) oot(3)(-9t^(-1)v^(4)) (p) oot(3)((2r-s)^(3)) #01.Simplify (ax16x5 b-3x-24x4 2x3(3x2 (c) x23 2x2y (d) 4x4y2 (e) (6x32 (f) (g) (h) xy-3 (i) 3y44y2-3 (j) 3x5y4z #02.Simplify the expression and rationalize the denominator when appropriate a81 b-216 c/512 (d) 1 (e) (f) 9x-4y6 (g) V8a6b-3 (h) V81r5s8 3x (i) 2y3 [2x4y4 (j) 9x 5x8y3 (k) 27x2 (1) 5x5y-24 (m) n5xy15x3y3 o/3t423/-9t-14 p)2r-s3 

          #01. Simplify.
(a) ((1)/(2)x^(4))(16x^(5))
(b) (-3x^(-2))(4x^(4))
(c) ((2x^(3))(3x^(2)))/((x^(2))^(3))
(d) ((2x^(2))^(3)y^(2))/(4x^(4)y^(2))
(e) ((1)/(6)a^(5))(-3a^(2))(4a^(7))
(f) ((6x^(3))^(2))/((2x^(2))^(3))(3x^(2))^(0)
(g) ((4a^(2)b)/(a^(3)b^(2)))((5a^(2)b)/(2b^(4)))
(h) ((1)/(3)x^(4)y^(-3))^(-2)
(i) (3y^(3))^(4)(4y^(2))^(-3)
(j) ((3x^(5)y^(4)z)/(x^(0)y^(-3)z))^(2)
#02. Simplify the expression and rationalize the denominator when appropriate.
(a) sqrt(81)
(b) 
oot(3)(-216)
(c) 
oot(4)(512)
(d) (1)/(
oot(3)(2))
(e) sqrt((1)/(5))
(f) sqrt(9x^(-4)y^(6))
(g) 
oot(3)(8a^(6)b^(-3))
(h) 
oot(4)(81r^(5)s^(8))
(i) sqrt((3x)/(2y^(3)))
(j) 
oot(3)((2x^(4)y^(4))/(9x))
(k) 
oot(4)((5x^(8)y^(3))/(27x^(2)))
(l) 
oot(4)((5x^(5)y^(-2))^(4))
(m) 
oot(5)((8x^(3))/(y^(4)))
oot(5)((4x^(4))/(y^(2)))
(n) sqrt(5xy^(7))sqrt(15x^(3)y^(3))
(o) 
oot(3)(3t^(4)v^(2))
oot(3)(-9t^(-1)v^(4))
(p) 
oot(3)((2r-s)^(3))
#01.Simplify (ax16x5 b-3x-24x4 2x3(3x2 (c) x23 2x2y (d) 4x4y2 (e) (6x32 (f)
(g) (h) xy-3 (i) 3y44y2-3 (j) 3x5y4z
#02.Simplify the expression and rationalize the denominator when appropriate a81 b-216 c/512 (d) 1
(e) (f) 9x-4y6 (g) V8a6b-3 (h) V81r5s8 3x (i) 2y3 [2x4y4 (j) 9x 5x8y3 (k) 27x2 (1) 5x5y-24
(m)
n5xy15x3y3 o/3t423/-9t-14 p)2r-s3
Show more…
01 simplify a 12x416x5 b 3x 24x4 c 2x33x2x23 d 2x23y24x4y2 e 16a5 3a24a7 f 6x322x233x20 g 4a2ba3b25a2b2b4 h 13x4y 3 2 i 3y344y2 3 j 3x5y4zx0y 3z2 02 simplify the expression and rationalize t 18442

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Precalculus with Limits
Precalculus with Limits
Ron Larson 2nd Edition
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#01. Simplify. (a) ((1)/(2)x^(4))(16x^(5)) (b) (-3x^(-2))(4x^(4)) (c) ((2x^(3))(3x^(2)))/((x^(2))^(3)) (d) ((2x^(2))^(3)y^(2))/(4x^(4)y^(2)) (e) ((1)/(6)a^(5))(-3a^(2))(4a^(7)) (f) ((6x^(3))^(2))/((2x^(2))^(3))(3x^(2))^(0) (g) ((4a^(2)b)/(a^(3)b^(2)))((5a^(2)b)/(2b^(4))) (h) ((1)/(3)x^(4)y^(-3))^(-2) (i) (3y^(3))^(4)(4y^(2))^(-3) (j) ((3x^(5)y^(4)z)/(x^(0)y^(-3)z))^(2) #02. Simplify the expression and rationalize the denominator when appropriate. (a) sqrt(81) (b) oot(3)(-216) (c) oot(4)(512) (d) (1)/( oot(3)(2)) (e) sqrt((1)/(5)) (f) sqrt(9x^(-4)y^(6)) (g) oot(3)(8a^(6)b^(-3)) (h) oot(4)(81r^(5)s^(8)) (i) sqrt((3x)/(2y^(3))) (j) oot(3)((2x^(4)y^(4))/(9x)) (k) oot(4)((5x^(8)y^(3))/(27x^(2))) (l) oot(4)((5x^(5)y^(-2))^(4)) (m) oot(5)((8x^(3))/(y^(4))) oot(5)((4x^(4))/(y^(2))) (n) sqrt(5xy^(7))sqrt(15x^(3)y^(3)) (o) oot(3)(3t^(4)v^(2)) oot(3)(-9t^(-1)v^(4)) (p) oot(3)((2r-s)^(3)) #01.Simplify (ax16x5 b-3x-24x4 2x3(3x2 (c) x23 2x2y (d) 4x4y2 (e) (6x32 (f) (g) (h) xy-3 (i) 3y44y2-3 (j) 3x5y4z #02.Simplify the expression and rationalize the denominator when appropriate a81 b-216 c/512 (d) 1 (e) (f) 9x-4y6 (g) V8a6b-3 (h) V81r5s8 3x (i) 2y3 [2x4y4 (j) 9x 5x8y3 (k) 27x2 (1) 5x5y-24 (m) n5xy15x3y3 o/3t423/-9t-14 p)2r-s3
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Transcript

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00:01 So i'm going to multiply my top and bottom by root 3 plus 1, because then by using difference of squares, the middle terms will cancel out, and i will have any radicals in the denominator.
00:11 So if you look, root 3 times root 3 is 9, and then i've got plus root 3 minus root 3, minus 1, when i foil it out.
00:19 And you can see that this root 3 and this root 3 cancel out, leaving me with just 8 ends in my denominator, which is what i wanted...
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