00:01
Hi, here in this given problem, wave speed in the wire, wire which is under tension.
00:26
This is given as c is equal to 24 meter per second.
00:36
Mass suspended with the wire to create a tension in it.
00:45
This is 3 kilogram.
00:50
So the tension created in the wire will be given by weight of this block mg.
01:02
In the first part of the problem, if we consider the linear mass density, means mass per unit length of the wire to be mu then the speed of the wave created over the string will be given by square root of t by mu or we can say this is m g by mu now for c this is 24 is equal to for the mass 3 kilogram g 9 .8 meter per second square divided by mu which is missing we have to find it.
01:59
Now squaring both the sides we get square of 24 this is 576 is equal to 9 .8 into 3.
02:21
This is 29 .4 divided by mu.
02:26
So this mu means linear mass density of the wire comes out to be equal to first of all it is given by 29 .4 divided by 576 and it comes out to be equal to 0 .0510 kilogram per meter or we can say this is 51 .0 gram per meter...