00:01
Okay, so question a, one has to determine the edge dimension of a cube that is a uranium 238 with a mass of 70 kilogram and a density of 18 .7 times 10 to 3 kilograms per cube.
00:38
So we can determine that from the density formula, which is this.
00:43
Lensity is equals to mass over the volume.
00:53
And you know that volume of a cube is its length raised to three.
01:01
Cube of its length.
01:07
So this length is what we are looking for.
01:11
And isolating it to the left sedentication since that we need, then we have then solving.
01:39
You can find this equals to 0 .155 meter or 15 .5 centimeter.
01:50
Now question be as for the decay energy.
01:54
So the energy per decay is equals to this.
01:58
The mass difference multiplied by squared off speed of light.
02:13
And so we, so these are the atomic masses.
02:38
So when you can find that the energy per decays equals to 51 .7 mp.
02:51
Now question c, want us to prove that the power output, is the decay energy multiplied by the decay rate.
03:12
So by definition, the power is energy per unit of time.
03:18
Now, since the energy per decay is as a unit of jose per decay, since an e .b can be converted to joles.
03:35
And the decay rate as a unit of decay per time.
03:42
So in case, suppose, seconds.
03:45
Therefore, if we multiply the energy per decay and the decay rate, we can determine b, which is a unit of joules per second.
03:58
So indeed, the power output is equal to the product of the energy per decay and the decay rate...