00:01
Now here the given differential equation is y double dash plus lambda y is equal to 0 where y dash 0 is equal to 0 which is also equal to y dash at pi.
00:15
Now case 1 when lambda is equal to 0 then y double dash is equal to 0.
00:23
Now this gives us y x is equal a plus b x where a and b are constant.
00:28
Now since y -dash 0 is equal to 0, and if we differentiate this, then y -dash -x is equal to b.
00:37
So we get b is equal to 0.
00:42
So this implies that y -x is equal to a.
00:47
Now since y -dash -pi is equal to 0, so here also b is equal to 0.
00:55
So we can say y -x is equal to a, is the eigen.
01:07
Function corresponding to eigenvalue lambda is equal to 0.
01:14
So this is one of the answer.
01:16
Now, case 2 when lambda is equal to alpha square which is greater than 0...