1 for each of the following indicate whether the ph would...

Name: 1 for each of the following indicate whether the ph would increase decrease or stay the same when each of the followed is added a solid naclo2 is added to hclo2 b solid rb
Uploaded: 2023-03-15T02:47:00-08:00
Duration: 6 min 59 s
Channel: Sri K
Description: 1 for each of the following indicate whether the ph would increase decrease or stay the same when each of the followed is added a solid naclo2 is added to hclo2 b solid rb

1. For each of the following indicate whether the pH would increase, decrease, or stay the same when each of the followed is added. a. solid NaClO2 is added to HClO2 ____________________________ b. solid RbNO3 is added to HNO3 ____________________________ c. solid HBr is added to KOH ____________________________ 2. Classify each of the following pairs as either a “buffer” or “not a buffer”. a.) HNO3/NaNO3 _____________________ b.) NH4Cl/NH3 _____________________ c.) HClO2/RbClO2 _____________________ d.) HI/CsI _____________________ 3.Calculate the pH of a solution prepared by combining 75.0mL of 0.125 M HC2H3O2 with 15.0mL of 0.075 M HCl. Ka = 1.8 × 10-5 4. The solubility of salts can be affected by other equilibria. Addition of all of the following will affect the solubility of FeCO3 EXCEPT: a. NaHCO3 b. NaCl c. H2CO3 d. Na2CO3 e. HCl

Transcript

00:01 The generic, if you see, a generic rate law, generic rate law for the given reaction will be r is the rate, is the rate constant multiplied with the concentration of ehtome to the power a, concentration of bromine to the power b, concentration of h plus to the power n.

00:28 And here given that the rate of disappearance, rate of these appearances are given.

00:41 Are given.

00:44 So in trial 1, in trial 1 we will see the rate as 1 will be equal to, the rate is 5 .7 times 10 to the power minus 5 that is equal to k 0 .3 to the power of a, 0 .0 .0.

01:02 050 to the power b 0 .050 to the power n and in trial two trial two the rate will be r2 is 5 .7 times 10 to the power minus 5 that is equal to k multiplied with 0 .3 to the power a 0 .1 to the power b 0 .0 .0 .0 5 050 to the power n.

01:30 If you see both the rates and divide rate 2 divided by rate 1.

01:41 So we will get r2 divided by r1 is k 0 .3 to the power a, 0 .11 to the power b, 0 .050 to the power n, divided by k 0 .0 .50 to the power a, 0 .50 to the power b, divided by k, k 0 .0 .5 0 to the power b, 0.

02:02 0 .050 to the power n.

02:04 So from these we will find out one because r2 and r1 are equal that is 5 .7 times 10 to the power minus 5 divided by 5 .7 times 10 to the power 5 so it will be 1 is equal to 2 to the power b hence we will get the value is 0 here we got the value of c b similarly if we'll find out similar it will divide r3, rate 3 divided by rate 1 we will get k 0 .3 to the power a, 0 .050 to the power, b value will be 0 .0 .01 to the power n, divided by k multiplied with 0 .3 to the power a, 0 .050 to the power b and b value is 0 .0 .0 .0 .0 .0.

03:03 050 to the power n.

03:05 From this we will get 2 to the power n is equal to 2 .1.

03:12 Hence, learn 2 .1 is equal to n learned 2.

03:17 That is, the value of n will be nearly equal to 1.

03:21 Here we got the value of the n.

03:24 Now we are going to find out the value of the 8.

03:27 If we will divide rate 5 to rate 1...