Question

(1 point) Let ($$a_n$$) be a sequence defined by the formula $$a_n = 7n + 1$$ for all integers $$n \ge 0$$. Determine whether this sequence satisfies the recursive relation $$a_n = a_{n-1} + 7$$. According to the formula that defines the sequence, $$a_n = \boxed{\phantom{7n+1}}$$. In order for the sequence to satisfy the recursive relation, it must be the case that $$a_{n-1} + 7$$ is equal to this. $$a_{n-1} = \boxed{\phantom{7(n-1)+1}}$$ $$a_{n-1} + 7 = \boxed{\phantom{7(n-1)+1+7}}$$ Is $$a_{n-1} + 7$$ equal to $$a_n$$? A. Yes B. No C. Not enough information given Does the sequence satisfy the recursive relation? A. Yes B. No C. Not enough information given

Name: 1 point let an be a sequence defined by the formula an 7n 1 for all integers n ge 0 determine whether this sequence satisfies the recursive relation an an 1 7 according to the formula th 25025
Uploaded: 2024-09-26T07:33:17-08:00
Duration: 1 min 2 s
Channel: Vysakh M
Description: 1 point let an be a sequence defined by the formula an 7n 1 for all integers n ge 0 determine whether this sequence satisfies the recursive relation an an 1 7 according to the formula th 25025

          (1 point) Let ($$a_n$$) be a sequence defined by the formula $$a_n = 7n + 1$$ for all integers $$n \ge 0$$. Determine whether this sequence satisfies the recursive relation
$$a_n = a_{n-1} + 7$$.

According to the formula that defines the sequence, $$a_n = \boxed{\phantom{7n+1}}$$. In order for the sequence to satisfy the recursive relation, it must be the case that $$a_{n-1} + 7$$ is equal to this.

$$a_{n-1} = \boxed{\phantom{7(n-1)+1}}$$
$$a_{n-1} + 7 = \boxed{\phantom{7(n-1)+1+7}}$$

Is $$a_{n-1} + 7$$ equal to $$a_n$$?
A. Yes
B. No
C. Not enough information given

Does the sequence satisfy the recursive relation?
A. Yes
B. No
C. Not enough information given

1 point let an be a sequence defined by the formula an 7n 1 for all integers n ge 0 determine whether this sequence satisfies the recursive relation an an 1 7 according to the formula th 25025

Added by Christian B.

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