00:01
Hey there, welcome to numerade.
00:03
Let's say we are given a weighted coin where tails is three times as likely as flipping a head.
00:11
So the coin here is flipped 10 times.
00:15
So what we know here is the probability of flipping a tail.
00:20
It's going to be three times the probability of flipping ahead.
00:24
So only the probability that works will be three fourths because three times the probability of flipping a tail.
00:31
Ahead is one -fourth, therefore three times one -fourth is equals three -fourths.
00:38
So that's how we got that here.
00:41
So therefore, we are going to be using the binomial distribution, since we're flipping in coin with two outcomes.
00:49
So we have n choose x times the probability raised to the x times q raised to the n minus x.
00:57
So what we're looking for here in terms of probabilities, um, we are going to be looking at one head or one tail.
01:08
It's the probability of one head or one tail.
01:24
All right, awesome.
01:27
So with this, we are going to be expanded this out into the calculation of the probability of one plus the probability of nine.
01:41
So we're going to be using the equation from above in which we have a sample size 10 and we're going to be using the following probability of one -fourth.
01:51
Okay, so one head and one tail...