1) Pure aluminum is produced from the electrolysis of excess Aluminum (III) ions over 32.8 hour period. When the cell is operated at 145.3A, what mass is produced in kg?
Added by Steven H.
Step 1
Q = 145.3 A x 32.8 hours x 3600 seconds/hour = 1.68 x 10^8 C 2) Determine the number of moles of electrons that have been transferred using Faraday's constant, F = 96,485 C/mol e-. n = Q/F = 1.68 x 10^8 C / 96,485 C/mol e- = 1745.5 mol e- 3) Determine the number Show more…
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