Question

1. The Bursar's Office is interested in reducing the time (in minutes) that customers must wait to reach a customer service representative. A sample of waiting times taken on Monday follows: 4.4, 3.5, 3.6, 4.9, 5.1, 7.3, 2.5, 3.6 a. (5%) Construct a stem-and-leaf display. b. (5%) Calculate the sample mean, median, range, and standard deviation. c. (3%) Calculate the 25th percentile for this data set. d. (2%) Is the data skewed? If so, which direction? e. (2%) What deductions from this sample of waiting times can you provide? HINT: do not simply reiterate the sample statistics you calculated above.

          1. The Bursar's Office is interested in reducing the time (in minutes) that customers must wait to reach a customer service representative. A sample of waiting times taken on Monday follows:

4.4, 3.5, 3.6, 4.9, 5.1, 7.3, 2.5, 3.6

a. (5%) Construct a stem-and-leaf display.

b. (5%) Calculate the sample mean, median, range, and standard deviation.

c. (3%) Calculate the 25th percentile for this data set.

d. (2%) Is the data skewed? If so, which direction?

e. (2%) What deductions from this sample of waiting times can you provide? HINT: do not simply reiterate the sample statistics you calculated above.

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1 the bursars office is interested in reducing the time in minutes that customers must wait to reach a customer service representative a sample of waiting times taken on monday follows 44 35 35105

Added by Eva G.

Elementary Statistics a Step by Step Approach

Allan G. Bluman 9th Edition

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Solved by Expert Kari Hasz

10/06/2022

Step 1

4, 3.5, 3.6, 4.9, 5.1, 7.3, 2.5, 3.6. To make calculations easier, we should sort the data in ascending order: 2.5, 3.5, 3.6, 3.6, 4.4, 4.9, 5.1, 7.3. The number of data points is $n = 8$. Show more…

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1. The Bursar's Office is interested in reducing the time (in minutes) that customers must wait to reach a customer service representative. A sample of waiting times taken on Monday follows: 4.4, 3.5, 3.6, 4.9, 5.1, 7.3, 2.5, 3.6 a. (5%) Construct a stem-and-leaf display. b. (5%) Calculate the sample mean, median, range, and standard deviation. c. (3%) Calculate the 25th percentile for this data set. d. (2%) Is the data skewed? If so, which direction? e. (2%) What deductions from this sample of waiting times can you provide? HINT: do not simply reiterate the sample statistics you calculated above.

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00:01 Suppose a bank branch located in a residential area is concerned with its service during the noon to 1 p .m.

00:07 Lunch hour.

00:08 The waiting times and minutes collected from a sample of 15 customers during this hour are listed below.

00:14 All right, so i've listed them here.

00:19 Part a, compute the mean and the median.

00:22 So the mean is 6 .9013.

00:28 The median is 6 .18.

00:33 For part b, compute the variance, standard deviation.

00:37 Range, coefficient of variance, and z scores.

00:42 So the variance is sometimes a little easier to find if you found the standard deviation.

00:49 So the standard deviation is 2 .1323, which means the variance is 4 .5467.

00:56 The range is 6 .7.

01:02 The coefficient of variance is the standard deviation divided by the mean, which is 0 .3090.

01:10 And for z scores, we have to do those for each one.

01:16 So remember z scores, you take the mean or your score minus the mean divided by the standard deviation.

01:24 So i'm just going to write the scores out.

01:26 So 1 .26, negative 0 .43, 0 .53, negative 0 .51, 0 .94, negative 1 .47, negative 0 .98 .8.

01:45 And i realize i have this score transpose, so let me fix that.

01:51 This should be 4 .82.

01:54 There we go...

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