00:01
The combustion of octane will give this reaction.
00:04
If 4 .3, 4 mole of octane combustion, then what volume of co2 will be produced at this temperature and this pressure? okay.
00:12
So first we will calculate the co2 from the help of the chemical reaction.
00:19
So 2c8h18 plus 25 mole of the oxygen that will give 60 mole of co2 plus 18 mole of the h2o.
00:35
Right? so now what we can say 434 mole of the octane.
00:41
Moll of this compound is the 434.
00:45
So what we can say, how many more of the co2 will be? 2 mole c8, h18 will give 16 mole of co2.
00:54
So mole of the co2 will be the 434 multiplied 16 divided by 2.
01:01
4, multiply 16 divided by 2, that will be equal to 3, 472.
01:09
Right, so mass of, we have calculated mole.
01:14
So volume we have to calculate, that is, nrt divided by pressure.
01:20
So mole is the 3, 472, multiply 1 by 12, multiply pressure.
01:29
Pressure is given 0995, multiply temperature...