Find the slope of the tangent line to the curve y^4 - 4y^2 = x^4 - 9x^2 at the point (3,2).
Added by Jessica J.
Step 1
Taking the derivative of both sides of the equation, we get: 4y^3(dy/dx) - 8y(dx/dx) = 4x^3( dx/dx) - 18x(dx/dx) Simplifying this expression, we get: (dy/dx) = [(2x^3 - y^3)/(2y - x)] Show more…
Show all steps
Close
Your feedback will help us improve your experience
Vipender Yadav and 97 other Precalculus educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
Find the slope of the tangent to the curve $y=\left(3 x-x^{2}\right)^{-2}$ at $\left(2, \frac{1}{4}\right)$
The Elasticity of Demand
The Derivatives of Composite Functions
Find the slope of the tangent curve y=x^4 - 2x^2 + 8 through point (2, 16)
Vishal P.
Find the slope of the tangent line to the graph at the given point. Cissoid: $(4-x) y^{2}=x^{3}$ Point: $(2,2)$
Differentiation
Implicit Differentiation
Recommended Textbooks
Precalculus with Limits
Precalculus
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD