Question

10) Treating the working substance as an ideal gas, show that the thermal efficiency of an engine operating in an idealized Otto cycle by equation: $e_{otto} = 1 - \frac{1}{({V_1}/{V_2})^{\gamma - 1}}$ Work outside) $e = 1 - \frac{T_c}{T_H}$ $AB = \frac{T_c}{T_H} ({\frac{V_1}{V_2}})^{1 - \gamma}$ so $e = 1 - ({\frac{V_1}{V_2}})^{1 - \gamma}$

          10) Treating the working substance as an ideal gas, show that the thermal efficiency of an engine operating
in an idealized Otto cycle by equation:
$e_{otto} = 1 - \frac{1}{({V_1}/{V_2})^{\gamma - 1}}$
Work outside)
$e = 1 - \frac{T_c}{T_H}$
$AB = \frac{T_c}{T_H} ({\frac{V_1}{V_2}})^{1 - \gamma}$ so $e = 1 - ({\frac{V_1}{V_2}})^{1 - \gamma}$

10) Treating the working substance as an ideal gas, show that the thermal efficiency of an engine operating
in an idealized Otto cycle by equation:
eotto = 1 - (1)/((V1/V2)^γ - 1)
Work outside)
e = 1 - (Tc)/(TH)
AB = (Tc)/(TH) ((V1)/(V2))^1 - γ so e = 1 - ((V1)/(V2))^1 - γ

Added by Lourdes C.

University Physics with Modern Physics

Hugh D. Young 14th Edition

Instant Answer

Solved by Expert Supratim Pal

10/24/2023

Step 1

Step 1: The thermal efficiency of an engine is defined as the ratio of the work done by the engine to the heat input. Show more…

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10) Treating the working substance as an ideal gas, show that the thermal efficiency of an engine operating in an idealized Otto cycle by equation: $e_{otto} = 1 - \frac{1}{(\frac{V_1}{V_2})^{y-1}}$ Work outside) $e = 1 - \frac{T_c}{T_H}$ $AB = \frac{T_c}{T_H}(\frac{V_1}{V_2})^{1-y}$ so $e = 1 - (\frac{V_1}{V_2})^{1-y}$