00:01
Hi, in this question we are given with a, so we have to find the gear diameter given the, given the number of, so number of gear teeth, so which is equal to, so this is 4 into 20 which is equal to 80 millimeter and we have to find the pitch diameter of the gear.
00:21
So, pitch diameter of the gear is given by d2 which is equal to 4 into t2.
00:27
So, t2 is the, so t2 is the meshing teeth which is equal to 4 into 100 that is equal to 400 millimeter or 400 meter.
00:39
Then we have, so then we have, so this is the value of d1, then we can write the gear ratio as, so gear ratio can be written as it is n1 by, so n2 by n1 is equal to t1 by t2.
00:55
So, we can write it as, so n2 will be the number of revolutions of the minor gear which is equal to t1 by t2 into n1.
01:06
So, we have this is 20 by 70 into 720 rpm.
01:11
So, we have n2 is equal to 144 rpm.
01:15
Now we have to find the, so now we can find the maximum permissible strength of the gear.
01:20
So, the permissible strength of the gear is given by, so permissible, so permissible strength of gear, so it is given by 600 divided by 2 which is equal to 300 newton per millimeter...