Question

= \sqrt{110.2545} = 3.202 2) The table shows the sample space for a mathematics class Sex Freshman Sophomore Junior Senior Total Female(Fe) 15 5 2 2 24 Male(M) 10 7 6 3 26 Total 25 12 8 5 50 If one student is selected at random from the class, find the probability that: a) The student is a freshman, P (Fr) = \frac{25}{50} = 0.5 b) The student is female, P (Fe) = \frac{24}{50} = 0.48 c) The student is male and sophomore, P (M and So) = \frac{7}{50} = 0.14 d) The student is either a female or a freshman, P (Fe or Fr) = \frac{24 + 25 - 15}{50} e) The student is a Junior given he is a male, P (Jr | M) =

          = \sqrt{110.2545} = 3.202
2) The table shows the sample space for a mathematics class
Sex	Freshman	Sophomore	Junior	Senior	Total
Female(Fe)	15	5	2	2	24
Male(M)	10	7	6	3	26
Total	25	12	8	5	50
If one student is selected at random from the class, find the probability that:
a) The student is a freshman, P (Fr) = \frac{25}{50} = 0.5
b) The student is female, P (Fe) = \frac{24}{50} = 0.48
c) The student is male and sophomore, P (M and So) = \frac{7}{50} = 0.14
d) The student is either a female or a freshman, P (Fe or Fr) = \frac{24 + 25 - 15}{50}
e) The student is a Junior given he is a male, P (Jr | M) =

= √(110.2545) = 3.202
2) The table shows the sample space for a mathematics class
Sex Freshman Sophomore Junior Senior Total
Female(Fe) 15 5 2 2 24
Male(M) 10 7 6 3 26
Total 25 12 8 5 50
If one student is selected at random from the class, find the probability that:
a) The student is a freshman, P (Fr) = (25)/(50) = 0.5
b) The student is female, P (Fe) = (24)/(50) = 0.48
c) The student is male and sophomore, P (M and So) = (7)/(50) = 0.14
d) The student is either a female or a freshman, P (Fe or Fr) = (24 + 25 - 15)/(50)
e) The student is a Junior given he is a male, P (Jr | M) =

Added by Lydia R.

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