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12) a) Show/draw the Miller-indexed direction of tungsten with BCC [111] and the Miller-index direction of aluminum with a FCC [111] on the right-hand coordinate system. b) Since the atomic radius of tungsten is 1.37 Å and the atomic radius of aluminum is 1.43 Å, calculate the lattice parameters of the systems. c) Calculate the atomic density of the directions. d) Which of the materials can be formed more easily.

          12) a) Show/draw the Miller-indexed direction of tungsten with BCC [111] and the Miller-index direction of aluminum with a FCC [111] on the right-hand coordinate system. b) Since the atomic radius of tungsten is 1.37 Å and the atomic radius of aluminum is 1.43 Å, calculate the lattice parameters of the systems. c) Calculate the atomic density of the directions. d) Which of the materials can be formed more easily.
        
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12) a) Show/draw the Miller-indexed direction of tungsten with BCC [111] and the Miller-index direction of aluminum with a FCC [111] on the right-hand coordinate system. b) Since the atomic radius of tungsten is 1.37 Å and the atomic radius of aluminum is 1.43 Å, calculate the lattice parameters of the systems. c) Calculate the atomic density of the directions. d) Which of the materials can be formed more easily.

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Chemistry: Structure and Properties
Chemistry: Structure and Properties
Nivaldo Tro 2nd Edition
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a) Show/draw the Miller-indexed direction of tungsten with BCC [111] and the Miller-index direction of aluminum with a FCC [111] on the right-hand coordinate system. b) Since the atomic radius of tungsten is 1.37 Ã… and the atomic radius of aluminum is 1.43 Ã…, calculate the lattice parameters of the systems. c) Calculate the atomic density of the directions. d) Which of the materials can be formed more easily?
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Transcript

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00:01 This question is similar to the previous one.
00:04 So aluminum is arranged in face -centered cubic structure arrangement.
00:22 The arrangement of atoms in this structure is such that eight atoms are present at eight corners of unit cell.
00:32 So 1 by 8 multiplied with 8 is equal to 1 atom, whereas 6 atoms are present at the center of each phases.
00:49 So half multiplied with 6 atoms equals 3 atoms.
00:57 So there are total of 4 atoms in fcc units.
01:04 Moving on to option b.
01:08 For this, the coordination number is 12 because each atom have 12 nearest neighboring atoms...
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