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New lab Events - Google Docs ? Netflix YouTube My Account Microsoft leams 1 Top Careers in Hum... V 122 Section 7.6: Problem 3 Previous Problem Problem List Next Problem (10 points) Let $R_1$, $R_2$ and $R_3$ be three disjoint events. If $Q$ is an event such that $P(R_1) = 0.16$, $P(R_2) = 0.29$, $P(R_3) = 0.55$, $P(Q \mid R_1) = 0.38$, $P(Q \mid R_2) = 0.32$, and $P(Q \mid R_3) = 0.43$, then $P(R_1 \mid Q) = $ $P(R_2 \mid Q) = $ .and $P(R_3 \mid Q) = $ (Hint: Draw a tree diagram first. Enter each of your answers to 3 decimal places.)

          New lab
Events - Google Docs ? Netflix YouTube My Account Microsoft leams 1 Top Careers in Hum... V
122 Section 7.6: Problem 3
Previous Problem
Problem List Next Problem
(10 points) Let $R_1$, $R_2$ and $R_3$ be three disjoint events. If $Q$ is an event such that
$P(R_1) = 0.16$, $P(R_2) = 0.29$, $P(R_3) = 0.55$, $P(Q \mid R_1) = 0.38$, $P(Q \mid R_2) = 0.32$, and $P(Q \mid R_3) = 0.43$,
then
$P(R_1 \mid Q) = $
$P(R_2 \mid Q) = $
.and
$P(R_3 \mid Q) = $
(Hint: Draw a tree diagram first. Enter each of your answers to 3 decimal places.)

New lab
Events - Google Docs ? Netflix YouTube My Account Microsoft leams 1 Top Careers in Hum... V
122 Section 7.6: Problem 3
Previous Problem
Problem List Next Problem
(10 points) Let R1, R2 and R3 be three disjoint events. If Q is an event such that
P(R1) = 0.16, P(R2) = 0.29, P(R3) = 0.55, P(Q | R1) = 0.38, P(Q | R2) = 0.32, and P(Q | R3) = 0.43,
then
P(R1 | Q) =
P(R2 | Q) =
.and
P(R3 | Q) =
(Hint: Draw a tree diagram first. Enter each of your answers to 3 decimal places.)

Added by Francisca C.

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