14. In the given figure, \(\triangle\) ABC and \(\triangle\) AMP are right angled at B and M respectively. Given AC = 10 cm, AP = 15 cm and PM = 12 cm. (i) Prove that : \(\triangle\) ABC ~ \(\triangle\) AMP (ii) Find : AB and BC. [2012]
Added by Austin C.
Close
Step 1
Step 1: Given that triangle ABC and triangle AMP are right angled at B and M respectively, we can conclude that angle ABC = angle AMP = 90 degrees. Show more…
Show all steps
Your feedback will help us improve your experience
Federico Castro and 82 other Geometry educators are ready to help you.
Ask a new question
Labs
Want to see this concept in action?
Explore this concept interactively to see how it behaves as you change inputs.
Key Concepts
Recommended Videos
In Fig. $6.39, \mathrm{ABC}$ and $\mathrm{AMP}$ are two right triangles, right angled at $\mathrm{B}$ and $\mathrm{M}$ respectively. Prove that: (i) $\Delta \mathrm{ABC}-\Delta \mathrm{AMP}$ (ii) $\frac{\mathrm{CA}}{\mathrm{PA}}=\frac{\mathrm{BC}}{\mathrm{MP}}$
Triangles
Similarity of Triangles
Erika B.
James K.
Recommended Textbooks
Geometry A Common Core Curriculum
Geometry
18,000,000+
Students on Numerade
Trusted by students at 8,000+ universities
Watch the video solution with this free unlock.
EMAIL
PASSWORD