00:01
Okay, so this question is about calculating the gibbs free energy for the reaction.
00:06
And for this reaction, if we write them down, 2 moles of the nitric acid reacts with 1 mole nitrogen monoxide, forms 3 moles no2 and 1 mole of the water.
00:36
So the question gives us the gibbs free energy, formation energy, for each compound.
00:46
So nitrogen acid, it's minus 110 .9, and for no, it's 87 .6, for no2, it's 51 .3, and for water, it's minus 237 .1.
01:06
So we want to know the gibbs free energy of this reaction.
01:11
And actually, how we do that? so the gibbs free energy of a reaction basically equals to the summation of the gibbs free energy of each of the reactant minus, the product minus the reaction gibbs free energy of the reactant.
01:37
So the formula is that the gibbs free energy of the reaction simply equals to the summation of the gibbs free energy of the product minus the summation of the gibbs free energy of the reactant.
01:57
And we can use this formula to do a calculation...