00:01
So here for part a, we can say that the pressure at point a, which would be half a meter below the open surface.
00:10
So this would be equalling then the atmospheric pressure plus row gd.
00:16
So this would be then 100 ,1 ,300 pascales plus the density of the oil, 900 kilograms per cubic meter, multiplied by 9 .8 meters per second squared, multiplied by 1 .00 meters minus 0 .5 meters.
00:42
So again, half a meter below the surface of the oil.
00:46
And we find that then the pressure at a would be equaling to 1 .06 times 10 to the 5th pascal's.
01:02
And so for part b, the pressure difference between point b and point a would then be equaling to, essentially, the atmospheric pressure cancels out in this sense.
01:18
And we are left with the density of the oil times the acceleration due to gravity multiplied by the depth of b minus the depth of point a...