00:02
1 .81 gram of h2 is allowed to react with the n2.
00:06
Then we will get ns 3.
00:07
What is the theoretical yield in the gram? what is the percentage yield of this reaction? okay.
00:14
So we have given n2 to nh3.
00:24
2ns 3.
00:24
So h2 mass is given 1 .81 .81 gram and mass of the nitrogen.
00:33
That is the 10 .5 gram.
00:35
10 .5 gram.
00:38
So mole will be equal to mass by molar mass.
00:41
28 divided by 2 28 that will be equal to 0 .37 1 .81 divided by 2 it will be equal to 0 .905 it is the mole right so what is the limiting reagent limiting reagent is the this one yes hydrogen is the limiting reagent h2 is the limiting reagent what is the theoretical in the ground so what we can say mole of the ammonia.
01:19
Mole of the ammonia will be what? 3 mole of the h2 will give 2 mole of the ammonia.
01:24
So 0 .905 multiplied 2 divided by 3.
01:35
It will be equal to 0 .603.
01:39
It is the theoretical yield...