00:01
So for our a part, the probability of n customers arriving in time, so n customers, arriving in time will be equal to, in time t will be equal to lambda t to the power n times e to the power minus lambda t over n factorial.
00:30
So for part i, 15 minutes interval will be called to t is equal to 15 minutes.
00:40
We have 15 and 60 which is equal to 0 .25 hours or al.
00:47
So our mean number for carons would be lambda times t so we have 0 .25 times 6 which is 1 .5.
00:57
For i .i which is 30 minutes interval we are going to get so this is for 15 and here is 30.
01:08
So we are going to get 30 on 60 which is 0 .5 hour.
01:14
So now our main number of occurrence will be lambda times t.
01:22
So we get 0 .5 times 6, which is equal to 3.
01:27
So now our probabilities running from 0 to 5 customers arriving will be.
01:40
So this will be our time interval.
01:43
We have 15 minutes and we have 30 minutes.
01:49
So this is the formula we are actually using to solve it.
01:53
So we need to know this so we have the mean number for currents let me write the mean so for 15 minutes we have 1 .5 and for 30 we have 3 when we come to x so here will be the probabilities so we are doing it from 0 to 5 so we have 0 so when we use the formula that i showed you earlier for here we are going to get 0 .223.
02:45
For here, 0.
02:47
So this is the lambda t.
02:50
You just need to factorize this in here.
02:58
And we already know what n is.
03:00
So if we are at 0, here will be 0, and here will be 0.
03:06
That's all.
03:08
So this is simple.
03:09
That's why making it a table form to make our work easy.
03:12
So we get 0.
03:15
498 and for 1 we get 0 .3347 and here too we get 0 .149 for 2.
03:31
You get 0 .25 10 and here is 0 .2402.
03:35
When we come here we get 0 .125.
03:35
When we come here we get 0 .125 and here to be 0 .240.
03:40
When we come here we get 0 .155 and here to be 0 .2.
03:48
For 0.
03:51
For the 4, we get 0 .0 .741 and 0 .1680.
04:02
4 5.
04:04
We get 0 .0 .141 and 0 .108.
04:13
When we come to the fat speed, a probability that the current system is idle would be equal to 1 minus b, which is 1 minus lambda and so this will be equal to 1 minus 0 .6.
04:31
So we get 0 .4...