00:01
In this problem, we have a object of mass 9 kg.
00:07
The object is hanging with the help of a light inextensible cord.
00:13
The cord passes through a massless and frictionless pulley and the cord is attached to a 5 kg mass.
00:21
This mass is sliding on a rough horizontal surface.
00:25
The coefficient of kinetic friction between the rough horizontal surface and 5 kg mass is 0 .2.
00:33
We have to find out the tension in the string.
00:36
Let's draw the forces.
00:38
On m2, the weight m2g act in the vertical downward direction.
00:43
The tension t act in the upward direction.
00:46
Since the cord is inextensible and massless, the tension throughout the cord is constant.
00:53
Hence, on m1, the tension t act to the rightward direction.
00:58
Now, we assume m2 is moving down.
01:02
Then m1 is sliding to the rightward direction...