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2. An equilateral triangle of side length 'l' at the center and at the midpoint of one side, where neutron sources of strengths S [neutrons/second] are placed at each one of the vertices. Carry on the calculations: a. In a vacuum, b. In a diffusing medium with a diffusion coefficient D and a diffusion length L. Note: Fick's law applies only in the case of a diffusing medium.

          2. An equilateral triangle of side length 'l' at the center and at the midpoint of one side,
where neutron sources of strengths S [neutrons/second] are placed at each one of the vertices.
Carry on the calculations:
a. In a vacuum,
b. In a diffusing medium with a diffusion coefficient D and a diffusion length L.
Note: Fick's law applies only in the case of a diffusing medium.
        
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2. An equilateral triangle of side length 'l' at the center and at the midpoint of one side,
where neutron sources of strengths S [neutrons/second] are placed at each one of the vertices.
Carry on the calculations:
a. In a vacuum,
b. In a diffusing medium with a diffusion coefficient D and a diffusion length L.
Note: Fick's law applies only in the case of a diffusing medium.

Added by Amber T.

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Chemistry: Structure and Properties
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Nivaldo Tro 2nd Edition
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An equilateral triangle of side length 'l' is located at the center and at the midpoint of one side, where neutron sources of strengths S [neutrons/second] are placed at each one of the vertices. Carry out the following calculations: a. In a vacuum. b. In a diffusing medium with a diffusion coefficient D and a diffusion length L. Note: Fick's law applies only in the case of a diffusing medium.
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00:01 Hello everyone so here we are going to find out the energy during the radiation so that should be the mass of proton minus the mass of deuteron minus the 2mc times d c squared so since we know that that should be the mass of proton minus the mass of duteron time c squared minus this is 2mc square and since this mp minus and since this mp minus and so that will be mn13 minus the mass of carbon 13 times the c square minus 2 times the 5 .11 a million electron volt...
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