00:01
In the given question we are told that a motion of the backhoe bucket shown with the cylinders ad cg and e f with theta equals to 45 degree.
00:15
Now we are told that a result of an attempt to disclose a portion of a slab force with 2 kith is exerted on a bucket teeth.
00:27
Now we have to determine the force exerted on each of this cylinder.
00:32
To determine the force exerted by cylinder c .g, we have to apply the equilibrium condition.
00:41
So take the moment about h, we write, sigma m, h should be 0.
00:49
So 4 by 5 f, cg 10 plus 3 by 5.
01:01
F cg 10 plus 2 cost 45 into 16 plus 2 sine 45 into 8 should be 0 so 14 force by cg plus 33 .94 equals to 0 so f cg will be 2 .c will be 2 .42 this is the comparative force acting on the member cg now apply the equilibrium condition and take moments about point b so we write mb equals to 0 this will be 4 by 5 f a d into 12 plus 3 by 5 f a d into 10 plus p cos theta 86 minus p sine theta 42 equals to 0 so evaluating this equation 9 .6 f a d plus 6 f ad plus 62 .22 equals to 0 so f ad will be 3 .99 gifts this comparative force acting on the member ad.
02:40
According to the free body diagram, the value of 10 beta will be 16 by 40.
02:48
So beta will be 10 inverse 0 .4 which is 21 .8 degree...