Question

2 points Save Answer A package contains 19 circuits, 6 of which are defective. If 7 are selected, The probability of getting all non-defective is The probability of 3 defective and 4 non-defective is Please, round up the answer to THREE decimal places (Exactly three decimals, not less and not more).

          2 points Save Answer
A package contains 19 circuits, 6 of which are defective. If 7 are
selected,
The probability of getting all non-defective is
The probability of 3 defective and 4 non-defective is
Please, round up the answer to THREE decimal places (Exactly
three decimals, not less and not more).

2 points Save Answer
A package contains 19 circuits, 6 of which are defective. If 7 are
selected,
The probability of getting all non-defective is
The probability of 3 defective and 4 non-defective is
Please, round up the answer to THREE decimal places (Exactly
three decimals, not less and not more).

Added by Robert V.

Elementary Statistics a Step by Step Approach

Allan G. Bluman 9th Edition

Instant Answer

Solved by Expert Jason Horton

Step 1

The total number of circuits is 19, and the number of defective circuits is 6. So, the number of non-defective circuits is 19 - 6 = 13. To calculate the probability of getting all non-defective circuits, we need to divide the number of ways to select 7 Show more…

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2 points Save Answer A package contains 19 circuits, 6 of which are defective. If 7 are selected, The probability of getting all non-defective is The probability of 3 defective and 4 non-defective is Please, round up the answer to THREE decimal places (Exactly three decimals, not less and not more).