Question

2) $g(x) = x + 2$ $f(x) = -2x$ Find $\left(\frac{g}{f}\right)(x)$ 4) $g(n) = 3n$ $f(n) = n^3 + 2$ Find $(3g - 5f)(n)$

          2) $g(x) = x + 2$
$f(x) = -2x$
Find $\left(\frac{g}{f}\right)(x)$
4) $g(n) = 3n$
$f(n) = n^3 + 2$
Find $(3g - 5f)(n)$

2) g(x) = x + 2
f(x) = -2x
Find ((g)/(f))(x)
4) g(n) = 3n
f(n) = n^3 + 2
Find (3g - 5f)(n)

Added by Kyle E.

Precalculus with Limits

Ron Larson 2nd Edition

Instant Answer

Solved by Expert Brent Burkett

Step 1

We can use the formula for the slope-intercept form of a linear equation: y = mx + b, where m is the slope and b is the y-intercept. In this case, we have: fx = -2x = m*r + b Since we know that r = -2, we can substitute that in: fx = -2m + b We also know that Show more…

Show all steps