Question

2. Right in the heart of China, the Macau Tower, Macau is the highest com- mercial bungee jump in the world with a maximum length of 233 m dur- ing stretch. When the bungee cord (rope) is un-stretch, its length is 180m. If a man weighing 500 N, dropped from the top of Macau tower, moved vertically down, and reach the maximum length of 233m before the cord compressing up, what then is the (a) force constant of the bungee cord, and (b) what is the stopping power of the bungee cord? (assume that air resistance and mass of the bungee cord are negligible) Given: total length = 233 m, un-stretch length = 180m, Ay= Weight of man= mg = 500N, g = 9.8 m/s2 Required: Force constant = ?, stopping power of Bungee cord = ? m = > Execute: Solve for us before the cord stretches: AGPE =mgh = AKE = 0.5mve v2 = 2gh = 2(9.8m/s2)(180m) = V=Uf= Solve for net acceleration due to the cord and earth's gravity; Ane= (1/2-1/2)/(2Ay) Initial v; is the final velocity before it stretches, while the new final v;= Fnet = -kAy, k = -Fnet/Ay = anet = -33.3m/s2, Fnet = manet = Solve for time elapsed to fully stretch the bungee cord; At = (U-1)/(Anet) = Solve for the stopping power of the bungee cord: AW = 0.5kAy?, Pstop =AW/At AW = 0.5k*Ay2 = Pstop =AW/At =

Name: 2 right in the heart of china the macau tower macau is the highest com mercial bungee jump in the world with a maximum length of 233 m dur ing stretch when the bungee cord rope is un stretch its lengt
Uploaded: 2023-05-09T05:57:31-08:00
Duration: 2 min 39 s
Channel: Numerade
Description: 2 right in the heart of china the macau tower macau is the highest com mercial bungee jump in the world with a maximum length of 233 m dur ing stretch when the bungee cord rope is un stretch its lengt

          2. Right in the heart of China, the Macau Tower, Macau is the highest com-
mercial bungee jump in the world with a maximum length of 233 m dur-
ing stretch. When the bungee cord (rope) is un-stretch, its length is 180m.
If a man weighing 500 N, dropped from the top of Macau tower, moved
vertically down, and reach the maximum length of 233m before the cord
compressing up, what then is the (a) force constant of the bungee cord,
and (b) what is the stopping power of the bungee cord? (assume that air
resistance and mass of the bungee cord are negligible)
Given: total length = 233 m, un-stretch length = 180m, Ay=
Weight of man= m*g = 500N, g = 9.8 m/s2
Required: Force constant = ?, stopping power of Bungee cord = ?
m =
>
Execute:
Solve for us before the cord stretches: AGPE =mgh = AKE = 0.5mve
v2 = 2gh = 2*(9.8m/s2)*(180m) =
V=Uf=
Solve for net acceleration due to the cord and earth's gravity; Ane= (1/2-1/2)/(2Ay)
Initial v; is the final velocity before it stretches, while the new final v;=
Fnet = -k*Ay, k = -Fnet/Ay =
anet = -33.3m/s2, Fnet = m*anet =
Solve for time elapsed to fully stretch the bungee cord; At = (U-1)/(Anet) =
Solve for the stopping power of the bungee cord: AW = 0.5k*Ay?, Pstop =AW/At
AW = 0.5k*Ay2
=
Pstop =AW/At =

Added by Rose F.

Question

Please give Ace some feedback