00:01
Okay, so we need to determine our rate law for this, and our rate is going to be some rate constant times the concentration of the iodide ion raised to some order, and the s2o8 2 - ion raised to some order.
00:18
So our goal is to figure out what those are.
00:20
So we're going to take a look first at reactions 1 and 2, or experiments 1 and 2.
00:25
Concentration of the s2o8 is held constant.
00:30
Okay, so this does not change.
00:31
So when we go from experiment two to experiment one, that was, we doubled our concentration.
00:39
And look at this, our rate also doubled.
00:42
So when you take two to some power, it equals two.
00:46
So this two is this two, and this two is this two.
00:51
And we're trying to determine what that is.
00:53
So two to the first power equals two.
00:55
So that tells us our order with respect to i, that was changing is 1.
01:01
All right, let's take a look at experiments 1 and 3.
01:07
So when we look at experiments 1 and 3, concentration of iodide is held constant.
01:12
When we go from experiment 3 to experiment 1, the concentration doubles.
01:18
And look at that, our rate also doubles.
01:21
So 2 to the what what power equals 2? again, this question mark right here is going to be 1...