00:02
Hello students, that question is based on an alpha particle.
00:07
So we are mentioned that name of that particle that is alpha particle and he says that is a length of a tube.
00:17
So we are considered l is given that is a 4 meter, okay? an initial speed that is a u is equivalent to 1 kilometer per second, okay? when the particle will be comes out from a that tube the velocity becomes a 9 km per second.
00:39
Find the time period for that hollow tube.
00:43
So we are just make a rough diagram when a particle moving inside so that is a u.
00:50
When it comes out the velocity becomes a v and that is a length of a that tube is given that is a 4 meter difference.
00:58
So, we can easily calculate the diagram and the value.
01:06
So by using a third equation, v square is equivalent to a u square plus 2 as.
01:14
So what is the v? so we are mentioned that is a 9 km per second, so 9 km becomes a 9 ,000 whole square equal to u squared that means 1 ,000 and this is whole square.
01:29
Plus 2 into a and the length is covered that is a 4 meter so 9 ,000 minus of a 1000 becomes a 9 ,000 minus 1 ,000 a minus b into 9 ,000 plus 1 ,000 a plus b so 8 into a now so it becomes a 8 ,000 multiply by 10 ,000 is equal to a 8a.
02:04
So, a can be calculated by a 8 cancel out the one time.
02:09
So these are 4 and 7 -0...