27.) A math debating team consists of 4 speakers. How many ways can the captain and vice-captain be chosen? A.) 10 B.) 12 C.) 14 D.) 16 28.) At a dinner party 6 men and 6 women sit at a round table. In how many ways can they sit if Bryan and Jell must sit together? A.) $2! \cdot 10!$ B.) $12! \cdot 10!$ C.) $12! \cdot 2!$ D.) $2! + 12!$
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) A math debating team consists of 10 speakers. The captain and vice captain can be chosen in 10*9 = 90 ways. ( Show more…
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