00:02
In this problem, you have a bisector of a triangle that splits the two sides opposite into segments 12 and 16, which means that this side right here was a total of 28 units long, and that one other side is 20.
00:19
We don't know if it's the bottom or top.
00:21
I'm just going to put at the bottom.
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And you want to find two possible values for this third side.
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What you need to remember is that three sides, sorry, you have what's called triangle inequality.
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Any two sides have to add to be greater than the third side.
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So we're going to call the side we're trying to find x.
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So we have x plus 20 has to be greater than 28.
00:56
That's one.
00:57
Whoops, this must be 28.
00:59
That's one possible equation.
01:02
And then 28 plus 20 has to be greater than x...