3. A 3.00-kHz tone is being produced by a speaker with a diameter of 0.175 m. The air temperature changes from 0 to 29 8C. Assuming air to be an ideal gas, find the change in the diffraction angle u. (11)
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The speed of sound in air can be calculated using the formula v = 331.4 + 0.6T, where v is the speed of sound and T is the temperature in Celsius. At 0°C, the speed of sound is v1 = 331.4 + 0.6*0 = 331.4 m/s. At 298°C, the speed of sound is v2 = 331.4 + Show more…
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A $3.00-\mathrm{kHz}$ tone is being produced by a speaker with a diameter of 0.175 $\mathrm{m}$ . The air temperature changes from 0 to $29^{\circ} \mathrm{C}$ . Assuming air to be an ideal gas, find the change in the diffraction angle $\theta$ .
A $3.00-\mathrm{kH} z$ tone is being produced by a speaker with a diameter of $0.175 \mathrm{~m}$. The air temperature changes from 0 to $29^{\circ} \mathrm{C}$. Assuming air to be an ideal gas, find the change in the diffraction angle $\theta .$
Sound exits a diffraction horn loudspeaker through a rectangular opening like a small doorway. Such a loudspeaker is mounted outside on a pole. In winter, when the temperature is 273 K, the diffraction angle $\theta$ has a value of $15.0^{\circ} .$ What is the diffraction angle for the same sound on a summer day when the temperature is 311 $k ?$
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