30 a pair of wedges is used to lift the crate as shown in...

Name: 30 a pair of wedges is used to lift the crate as shown in fig 3 the crate has a weight of 1200 n the wedge angle theta 10 the static friction coefficient between wedges a and b is 035 and be 40628
Uploaded: 2020-06-26T16:44:59-08:00
Duration: 4 min 38 s
Channel: Vipender Yadav
Description: 30 a pair of wedges is used to lift the crate as shown in fig 3 the crate has a weight of 1200 n the wedge angle theta 10 the static friction coefficient between wedges a and b is 035 and be 40628

[30%] A pair of wedges is used to lift the crate as shown in Fig. 3. The crate has a weight of 1200 N , the wedge angle theta= 10^(@), the static friction coefficient between wedges A and B is 0.35, and between other surfaces is 0.10. Specify the minimum force P required to move the wedge to the right. Neglect the weight of the wedges.

Transcript

00:01 So here in this problem we have to find the minimum force p which is required to move this 800 kg block with the help of two eight degrees fitches and we are given that the coefficient of static friction between all surfaces is 0 .3 now first of all we'll be calculating the weight of this block so weight we know it is a mass into g and g is acceleration due to gravity whose value is 9 .81 so 800 kg times 9 .81 meter per second square.

00:34 So after solving we'll get 7 848 newton.

00:39 So this is the weight of the block and if we calculate the angle of friction.

00:46 So angle of friction would be 5 s that is 10 inverse mu and mu we know it is 0 .3 tangent inverse 0 .3 which comes out to be as nearly 16 .7 degree.

01:02 So this is the fi s next we'll be making the free board diagram of this 800 kg block and this left side wedge so this is a free board diagram now if we calculate the angle of r1 the angle made by the reaction force r1 with the horizontal it will be equals to 16 .7 degree plus 8 degree and that comes out to be as nearly 24 .7 degree.

01:37 So let name this angle this whole angle to be as theta 1.

01:41 Now here you can observe that there are only three forces acting on this whole block and the wedge so we can make a force triangle and that will make our things easier to solve.

01:52 So let's make a force triangle now.

01:55 So this is a force triangle.

01:59 Now we can apply the sign rule to find the value of r1 but before doing so we'll calculate the angle alpha.

02:08 We know this whole angle this if you include if you see this total angle it is 90 degree that means 16 .7 degree plus alpha plus 24 .70 degree it is equal to 90 degree from here alpha comes out to be as 48 .6 degree now we can apply the sign rule to find the value of r1 so r1 divide by this angle sign of this angle sign of this angle to sign 16 .7 degree it will be equals to this force that is 7 848 newton divide by this angle this alpha angle sign alpha so alpha we know it is 48 .6 degree from here r1 comes out to be as 3 ,06 .5 newton so this is the value of r1 next we'll be making the free border diagram of this second wedge to calculate the value of p...

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