00:01
All right, so our first question here, which i'll call a, is a reaction where we're trying to figure out the total amount of energy that is lost.
00:14
Now, the formula we use for that is q equals mc delta t, and q is going to be what we're solving for.
00:21
Now, the mass of the solution is going to be 3 .8 grams of the sodium bicarbonate plus 25 grams of the hydrochloric acid.
00:33
And they're all put together.
00:34
The reason why i'm using 25 grams is the density of the hydrochloric acid solution is going to be about 1 gram per centimeter cubed.
00:44
So i'm just substituting that in.
00:46
We're also going to take the assumption that the specific heat of the hydrochloric acid is also going to be about 4 .18 joules per gram degree celsius because the hydrochloric acid is extremely dilute.
01:03
So it's almost all water.
01:05
So therefore, the density of water and the specific heat of water can be used in our problem.
01:09
And then the change in temperature it said the temperature went down by 9 .5 degrees celsius so we're gonna say minus 9 .5 degrees celsius so you can see the degrees celsius are gonna cancel and the grams are gonna cancel so we'll end up with an answer in joules which will be your answer part a let's see what that is here so that's gonna be twenty eight point eight times four point one eight times 9 .5, which is negative.
01:42
Sorry, let me try this one more time...