A 12 cm 15 cm M 16cm N x 4cm y B C a) Tính x; y? Bi?t MN \parallel BC 25cm A 12cm K x 36 cm C c) Tính x? Bi?t BK là ?g p/g c?a B
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42 cm mGh 28 wgk 2 Hom L0 R xx YL 6o 29 I Ih ma NZim wsp 98 CM c Tnh 6 7 Did p 2 9 T9 cua 03 Show more…
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0 mass weighing 24 pounds attached to the spring stretches 0.5 inches below the equilibrium position. Finally, the motion is at 92.32 ft/s^2 for the equation of acceleration due to gravity (g).
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Useful constants: k = 9.0 x 10^9 N.m^2/C^2 ε₀ = 8.85 x 10^-12 C^2/N.m^2 μ₀ = 4π x 10^-7 T.m/A mp = 1.67 x 10^-27 kg me = 9.1 x 10^-31 kg e = 1.6 x 10^-19 C g = 10.0 m/s^2
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ACTIVITY 2.1 CONSERVATION OF MECHANICAL ENERGY Directions: Complete the table below which gives the height, gravitational potential, and kinetic energy of a falling object (m = 2.0 kg; g ≈ 10 m/s²) Note: DON'T include the UNITS in your final answer and kindly ROUND OFF to the nearest HUNDREDTHS. Position | Height (m) | Speed (m/s) | PEgrav (J) | KE (J) | Total Energy (J) A | 10 | 0 | 200 | 0 | (8.) B | 8 | 6.32 | 160 | (5.) | (9.) C | (1.) | 10 | 100 | (6.) | (10.) D | (2.) | 12.65 | (3.) | 160 | (11.) E | 0 | 14.14 | (4.) | (7.) | (12.) Refer to the equations below: KE = 1/2 mv² GPE = mgh TME = KE + GPE
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